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-51x+210=-3x^2
We move all terms to the left:
-51x+210-(-3x^2)=0
We get rid of parentheses
3x^2-51x+210=0
a = 3; b = -51; c = +210;
Δ = b2-4ac
Δ = -512-4·3·210
Δ = 81
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{81}=9$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-51)-9}{2*3}=\frac{42}{6} =7 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-51)+9}{2*3}=\frac{60}{6} =10 $
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